(3x-4)+(x-4)=56

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Solution for (3x-4)+(x-4)=56 equation: 



(3x-4)+(x-4)=56

We move all terms to the left:

(3x-4)+(x-4)-(56)=0

We get rid of parentheses

3x+x-4-4-56=0

We add all the numbers together, and all the variables

4x-64=0

We move all terms containing x to the left, all other terms to the right

4x=64

x=64/4

x=16

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