(3x-4)+(5x+1)=(7x-27)

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Solution for (3x-4)+(5x+1)=(7x-27) equation: 



(3x-4)+(5x+1)=(7x-27)

We move all terms to the left:

(3x-4)+(5x+1)-((7x-27))=0

We get rid of parentheses

3x+5x-((7x-27))-4+1=0



We calculate terms in parentheses: -((7x-27)), so:

(7x-27)

We get rid of parentheses

7x-27

Back to the equation:

-(7x-27)



We add all the numbers together, and all the variables

8x-(7x-27)-3=0

We get rid of parentheses

8x-7x+27-3=0

We add all the numbers together, and all the variables

x+24=0

We move all terms containing x to the left, all other terms to the right

x=-24

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