(3x-4)(2x-1)-((3x+1)(x-3)=(3x-1)(x-1)

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Solution for (3x-4)(2x-1)-((3x+1)(x-3)=(3x-1)(x-1) equation: 



(3x-4)(2x-1)-((3x+1)(x-3)=(3x-1)(x-1)

We move all terms to the left:

(3x-4)(2x-1)-((3x+1)(x-3)-((3x-1)(x-1))=0

We multiply parentheses ..

(+6x^2-3x-8x+4)-((3x+1)(x-3)-((3x-1)(x-1))=0



We calculate terms in parentheses: -((3x+1)(x-3)-((3x-1)(x-1)), so:

(3x+1)(x-3)-((3x-1)(x-1)

We multiply parentheses ..

(+3x^2-9x+x-3)-((3x-1)(x-1)



We calculate terms in parentheses: -((3x-1)(x-1), so:

(3x-1)(x-1



We get rid of parentheses

3x^2-9x+x-((3x-1)(x-1)-3

We multiply parentheses ..

3x^2-((+3x^2-3x-1x+1)-3-9x+x

Back to the equation:

-(3x^2-((+3x^2-3x-1x+1)-3-9x+x)



We get rid of parentheses

6x^2-(3x^2-((+3x^2-3x-1x+1)-3-9x+x)-3x-8x+4=0

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