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(3x-39)=(2x+24)
We move all terms to the left:
(3x-39)-((2x+24))=0
We get rid of parentheses
3x-((2x+24))-39=0
We calculate terms in parentheses: -((2x+24)), so:We get rid of parentheses
(2x+24)
We get rid of parentheses
2x+24
Back to the equation:
-(2x+24)
3x-2x-24-39=0
We add all the numbers together, and all the variables
x-63=0
We move all terms containing x to the left, all other terms to the right
x=63
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