If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(3x-35)+(7x-15)=180
We move all terms to the left:
(3x-35)+(7x-15)-(180)=0
We get rid of parentheses
3x+7x-35-15-180=0
We add all the numbers together, and all the variables
10x-230=0
We move all terms containing x to the left, all other terms to the right
10x=230
x=230/10
x=23
| 81=7d+4 | | –3z−16z+1=–7−19z | | x/1+6=8 | | (5x-5)+(6x-8)=61 | | 3(n−2)+n=18 | | A3=n+8 | | 9x-8(x-5)=46 | | (5x-5)+(6x-8)=56 | | -2-8w=-3w-4w-18 | | 0=7x-7;x | | (10x-19)(3x+4)=180 | | X+25x=1040 | | 6x+1+91=180 | | 3x-12=9;x | | 10m−24=8m−10 | | A2=n+8 | | g^2=25/36 | | 1.5-0.03x=-1.47 | | 3x-12=9;x | | 15+100r=2.50r | | (5x-5)+(6x-8)=44 | | 25+4x+1=21 | | 10=3x-2;x | | 16=p/12 | | (5x-5)+(6x-8)=40 | | 18=27.3x | | 6y-2=6y-2 | | 5x+6=21;x | | 8-8t=-2t-6t+8 | | x+4=3x+28 | | √(x^2+x+1)−√(x^2+x−1)=1 | | x+7.8=-20 |