(3x-33)(2x+26)=90

Solution for (3x-33)(2x+26)=90 equation:

(3x-33)(2x+26)=90

We move all terms to the left:

(3x-33)(2x+26)-(90)=0

We multiply parentheses ..

(+6x^2+78x-66x-858)-90=0

We get rid of parentheses

6x^2+78x-66x-858-90=0

We add all the numbers together, and all the variables

6x^2+12x-948=0

a = 6; b = 12; c = -948;
Δ = b2-4ac
Δ = 122-4·6·(-948)
Δ = 22896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{22896}=\sqrt{144*159}=\sqrt{144}*\sqrt{159}=12\sqrt{159}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12\sqrt{159}}{2*6}=\frac{-12-12\sqrt{159}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12\sqrt{159}}{2*6}=\frac{-12+12\sqrt{159}}{12}
$