(3x-3)/24=(x-4)/3

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Solution for (3x-3)/24=(x-4)/3 equation: 



(3x-3)/24=(x-4)/3

We move all terms to the left:

(3x-3)/24-((x-4)/3)=0

We calculate fractions


3x/()+(-((x-4)*24)/()=0



We calculate terms in parentheses: +(-((x-4)*24)/(), so:

-((x-4)*24)/(

We multiply all the terms by the denominator


-((x-4)*24)



We calculate terms in parentheses: -((x-4)*24), so:

(x-4)*24

We multiply parentheses

24x-96

Back to the equation:

-(24x-96)



We get rid of parentheses

-24x+96

Back to the equation:

+(-24x+96)



We get rid of parentheses

3x/()-24x+96=0

We multiply all the terms by the denominator


3x-24x*()+96*()=0

We add all the numbers together, and all the variables

3x-24x*()=0

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