(3x-28)=(2x+33)

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Solution for (3x-28)=(2x+33) equation: 



(3x-28)=(2x+33)

We move all terms to the left:

(3x-28)-((2x+33))=0

We get rid of parentheses

3x-((2x+33))-28=0



We calculate terms in parentheses: -((2x+33)), so:

(2x+33)

We get rid of parentheses

2x+33

Back to the equation:

-(2x+33)



We get rid of parentheses

3x-2x-33-28=0

We add all the numbers together, and all the variables

x-61=0

We move all terms containing x to the left, all other terms to the right

x=61

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