(3x-28)+(x+2)=90

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Solution for (3x-28)+(x+2)=90 equation: 



(3x-28)+(x+2)=90

We move all terms to the left:

(3x-28)+(x+2)-(90)=0

We get rid of parentheses

3x+x-28+2-90=0

We add all the numbers together, and all the variables

4x-116=0

We move all terms containing x to the left, all other terms to the right

4x=116

x=116/4

x=29

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