(3x-20)=(4x+11)

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Solution for (3x-20)=(4x+11) equation: 



(3x-20)=(4x+11)

We move all terms to the left:

(3x-20)-((4x+11))=0

We get rid of parentheses

3x-((4x+11))-20=0



We calculate terms in parentheses: -((4x+11)), so:

(4x+11)

We get rid of parentheses

4x+11

Back to the equation:

-(4x+11)



We get rid of parentheses

3x-4x-11-20=0

We add all the numbers together, and all the variables

-1x-31=0

We move all terms containing x to the left, all other terms to the right

-x=31

x=31/-1

x=-31

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