(3x-20)+(47-x-10)=180

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Solution for (3x-20)+(47-x-10)=180 equation: 



(3x-20)+(47-x-10)=180

We move all terms to the left:

(3x-20)+(47-x-10)-(180)=0

We add all the numbers together, and all the variables

(3x-20)+(-1x+37)-180=0

We get rid of parentheses

3x-1x-20+37-180=0

We add all the numbers together, and all the variables

2x-163=0

We move all terms containing x to the left, all other terms to the right

2x=163

x=163/2

x=81+1/2

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