(3x-2)=(7x+1)/7

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Solution for (3x-2)=(7x+1)/7 equation: 



(3x-2)=(7x+1)/7

We move all terms to the left:

(3x-2)-((7x+1)/7)=0

We get rid of parentheses

3x-((7x+1)/7)-2=0

We multiply all the terms by the denominator


3x*7)-((7x+1)-2*7)=0

We add all the numbers together, and all the variables

3x*7)-((7x+1)=0

Wy multiply elements

21x^2=0

a = 21; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·21·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{42}=0$

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