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(3x-2)=(2x+5)
We move all terms to the left:
(3x-2)-((2x+5))=0
We get rid of parentheses
3x-((2x+5))-2=0
We calculate terms in parentheses: -((2x+5)), so:We get rid of parentheses
(2x+5)
We get rid of parentheses
2x+5
Back to the equation:
-(2x+5)
3x-2x-5-2=0
We add all the numbers together, and all the variables
x-7=0
We move all terms containing x to the left, all other terms to the right
x=7
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