(3x-2)/7=(6x-5)/13

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Solution for (3x-2)/7=(6x-5)/13 equation: 


x in (-oo:+oo)

(3*x-2)/7 = (6*x-5)/13 // - (6*x-5)/13

(3*x-2)/7-((6*x-5)/13) = 0

(3*x-2)/7+(-1*(6*x-5))/13 = 0

(13*(3*x-2))/(7*13)+(-1*7*(6*x-5))/(7*13) = 0

13*(3*x-2)-1*7*(6*x-5) = 0

9-3*x = 0

(9-3*x)/(7*13) = 0

(9-3*x)/(7*13) = 0 // * 7*13

9-3*x = 0

9-3*x = 0 // - 9

-3*x = -9 // : -3

x = -9/(-3)

x = 3

x = 3

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