(3x-2)/7=(4x-1)/5

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Solution for (3x-2)/7=(4x-1)/5 equation: 


x in (-oo:+oo)

(3*x-2)/7 = (4*x-1)/5 // - (4*x-1)/5

(3*x-2)/7-((4*x-1)/5) = 0

(3*x-2)/7+(-1*(4*x-1))/5 = 0

(5*(3*x-2))/(5*7)+(-1*7*(4*x-1))/(5*7) = 0

5*(3*x-2)-1*7*(4*x-1) = 0

-13*x-3 = 0

(-13*x-3)/(5*7) = 0

(-13*x-3)/(5*7) = 0 // * 5*7

-13*x-3 = 0

-13*x-3 = 0 // + 3

-13*x = 3 // : -13

x = 3/(-13)

x = -3/13

x = -3/13

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