(3x-2)/5=4-(x+2)/3

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Solution for (3x-2)/5=4-(x+2)/3 equation: 



(3x-2)/5=4-(x+2)/3

We move all terms to the left:

(3x-2)/5-(4-(x+2)/3)=0

We calculate fractions


3x/()+(-(4-(x+2)*5)/()=0



We calculate terms in parentheses: +(-(4-(x+2)*5)/(), so:

-(4-(x+2)*5)/(

We multiply all the terms by the denominator


-(4-(x+2)*5)



We calculate terms in parentheses: -(4-(x+2)*5), so:

4-(x+2)*5

determiningTheFunctionDomain
-(x+2)*5+4

We multiply parentheses

-5x-10+4

We add all the numbers together, and all the variables

-5x-6

Back to the equation:

-(-5x-6)



We get rid of parentheses

5x+6

Back to the equation:

+(5x+6)



We get rid of parentheses

3x/()+5x+6=0

We multiply all the terms by the denominator


3x+5x*()+6*()=0

We add all the numbers together, and all the variables

3x+5x*()=0

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