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(3x-2)(-4x+1)=0
We multiply parentheses ..
(-12x^2+3x+8x-2)=0
We get rid of parentheses
-12x^2+3x+8x-2=0
We add all the numbers together, and all the variables
-12x^2+11x-2=0
a = -12; b = 11; c = -2;
Δ = b2-4ac
Δ = 112-4·(-12)·(-2)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-5}{2*-12}=\frac{-16}{-24} =2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+5}{2*-12}=\frac{-6}{-24} =1/4 $
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