(3x-17)+(27+40)+(2x-5)=180

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Solution for (3x-17)+(27+40)+(2x-5)=180 equation: 



(3x-17)+(27+40)+(2x-5)=180

We move all terms to the left:

(3x-17)+(27+40)+(2x-5)-(180)=0

determiningTheFunctionDomain
(3x-17)+(2x-5)-180+(27+40)=0

We add all the numbers together, and all the variables

(3x-17)+(2x-5)-180+67=0

We add all the numbers together, and all the variables

(3x-17)+(2x-5)-113=0

We get rid of parentheses

3x+2x-17-5-113=0

We add all the numbers together, and all the variables

5x-135=0

We move all terms containing x to the left, all other terms to the right

5x=135

x=135/5

x=27

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