(3x-15)=(2x-7)+(6x+4)

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Solution for (3x-15)=(2x-7)+(6x+4) equation: 



(3x-15)=(2x-7)+(6x+4)

We move all terms to the left:

(3x-15)-((2x-7)+(6x+4))=0

We get rid of parentheses

3x-((2x-7)+(6x+4))-15=0



We calculate terms in parentheses: -((2x-7)+(6x+4)), so:

(2x-7)+(6x+4)

We get rid of parentheses

2x+6x-7+4

We add all the numbers together, and all the variables

8x-3

Back to the equation:

-(8x-3)



We get rid of parentheses

3x-8x+3-15=0

We add all the numbers together, and all the variables

-5x-12=0

We move all terms containing x to the left, all other terms to the right

-5x=12

x=12/-5

x=-2+2/5

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