(3x-15)+(8x-40)=22

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Solution for (3x-15)+(8x-40)=22 equation: 



(3x-15)+(8x-40)=22

We move all terms to the left:

(3x-15)+(8x-40)-(22)=0

We get rid of parentheses

3x+8x-15-40-22=0

We add all the numbers together, and all the variables

11x-77=0

We move all terms containing x to the left, all other terms to the right

11x=77

x=77/11

x=7

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