(3x-15)+(4x-12)=32

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Solution for (3x-15)+(4x-12)=32 equation: 



(3x-15)+(4x-12)=32

We move all terms to the left:

(3x-15)+(4x-12)-(32)=0

We get rid of parentheses

3x+4x-15-12-32=0

We add all the numbers together, and all the variables

7x-59=0

We move all terms containing x to the left, all other terms to the right

7x=59

x=59/7

x=8+3/7

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