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(3x-15)(2x-5)=0
We multiply parentheses ..
(+6x^2-15x-30x+75)=0
We get rid of parentheses
6x^2-15x-30x+75=0
We add all the numbers together, and all the variables
6x^2-45x+75=0
a = 6; b = -45; c = +75;
Δ = b2-4ac
Δ = -452-4·6·75
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-15}{2*6}=\frac{30}{12} =2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+15}{2*6}=\frac{60}{12} =5 $
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