(3x-12)=(x+6)

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Solution for (3x-12)=(x+6) equation: 



(3x-12)=(x+6)

We move all terms to the left:

(3x-12)-((x+6))=0

We get rid of parentheses

3x-((x+6))-12=0



We calculate terms in parentheses: -((x+6)), so:

(x+6)

We get rid of parentheses

x+6

Back to the equation:

-(x+6)



We get rid of parentheses

3x-x-6-12=0

We add all the numbers together, and all the variables

2x-18=0

We move all terms containing x to the left, all other terms to the right

2x=18

x=18/2

x=9

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