(3x-12)/(16-4x)

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Solution for (3x-12)/(16-4x) equation: 


D( x )

16-(4*x) = 0

16-(4*x) = 0

16-(4*x) = 0

16-4*x = 0

16-4*x = 0 // - 16

-4*x = -16 // : -4

x = -16/(-4)

x = 4

x in (-oo:4) U (4:+oo)

(3*x-12)/(16-(4*x)) = 0

(3*x-12)/(16-4*x) = 0

3*x-12 = 0 // + 12

3*x = 12 // : 3

x = 12/3

x = 4

x in { 4} 

x belongs to the empty set

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