(3x-12)+(x+30)+(2x)=180

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Solution for (3x-12)+(x+30)+(2x)=180 equation:



(3x-12)+(x+30)+(2x)=180
We move all terms to the left:
(3x-12)+(x+30)+(2x)-(180)=0
We add all the numbers together, and all the variables
2x+(3x-12)+(x+30)-180=0
We get rid of parentheses
2x+3x+x-12+30-180=0
We add all the numbers together, and all the variables
6x-162=0
We move all terms containing x to the left, all other terms to the right
6x=162
x=162/6
x=27

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