(3x-12)+(9x-12)+(27x-12)=123

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Solution for (3x-12)+(9x-12)+(27x-12)=123 equation: 



(3x-12)+(9x-12)+(27x-12)=123

We move all terms to the left:

(3x-12)+(9x-12)+(27x-12)-(123)=0

We get rid of parentheses

3x+9x+27x-12-12-12-123=0

We add all the numbers together, and all the variables

39x-159=0

We move all terms containing x to the left, all other terms to the right

39x=159

x=159/39

x=4+1/13

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