(3x-12)+(4x-15)=29

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Solution for (3x-12)+(4x-15)=29 equation: 



(3x-12)+(4x-15)=29

We move all terms to the left:

(3x-12)+(4x-15)-(29)=0

We get rid of parentheses

3x+4x-12-15-29=0

We add all the numbers together, and all the variables

7x-56=0

We move all terms containing x to the left, all other terms to the right

7x=56

x=56/7

x=8

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