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(3x-12)(2x+5)=0
We multiply parentheses ..
(+6x^2+15x-24x-60)=0
We get rid of parentheses
6x^2+15x-24x-60=0
We add all the numbers together, and all the variables
6x^2-9x-60=0
a = 6; b = -9; c = -60;
Δ = b2-4ac
Δ = -92-4·6·(-60)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1521}=39$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-39}{2*6}=\frac{-30}{12} =-2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+39}{2*6}=\frac{48}{12} =4 $
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