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(3x-11)=(2x+16)
We move all terms to the left:
(3x-11)-((2x+16))=0
We get rid of parentheses
3x-((2x+16))-11=0
We calculate terms in parentheses: -((2x+16)), so:We get rid of parentheses
(2x+16)
We get rid of parentheses
2x+16
Back to the equation:
-(2x+16)
3x-2x-16-11=0
We add all the numbers together, and all the variables
x-27=0
We move all terms containing x to the left, all other terms to the right
x=27
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