(3x-11)+(x+14)+(3x-5)=180

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Solution for (3x-11)+(x+14)+(3x-5)=180 equation: 



(3x-11)+(x+14)+(3x-5)=180

We move all terms to the left:

(3x-11)+(x+14)+(3x-5)-(180)=0

We get rid of parentheses

3x+x+3x-11+14-5-180=0

We add all the numbers together, and all the variables

7x-182=0

We move all terms containing x to the left, all other terms to the right

7x=182

x=182/7

x=26

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