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(3x-11)(2x+11)=0
We multiply parentheses ..
(+6x^2+33x-22x-121)=0
We get rid of parentheses
6x^2+33x-22x-121=0
We add all the numbers together, and all the variables
6x^2+11x-121=0
a = 6; b = 11; c = -121;
Δ = b2-4ac
Δ = 112-4·6·(-121)
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3025}=55$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-55}{2*6}=\frac{-66}{12} =-5+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+55}{2*6}=\frac{44}{12} =3+2/3 $
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