(3x-10)=(2x+30)

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Solution for (3x-10)=(2x+30) equation: 



(3x-10)=(2x+30)

We move all terms to the left:

(3x-10)-((2x+30))=0

We get rid of parentheses

3x-((2x+30))-10=0



We calculate terms in parentheses: -((2x+30)), so:

(2x+30)

We get rid of parentheses

2x+30

Back to the equation:

-(2x+30)



We get rid of parentheses

3x-2x-30-10=0

We add all the numbers together, and all the variables

x-40=0

We move all terms containing x to the left, all other terms to the right

x=40

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