(3x-10)=(2x+20)+90

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Solution for (3x-10)=(2x+20)+90 equation: 



(3x-10)=(2x+20)+90

We move all terms to the left:

(3x-10)-((2x+20)+90)=0

We get rid of parentheses

3x-((2x+20)+90)-10=0



We calculate terms in parentheses: -((2x+20)+90), so:

(2x+20)+90

We get rid of parentheses

2x+20+90

We add all the numbers together, and all the variables

2x+110

Back to the equation:

-(2x+110)



We get rid of parentheses

3x-2x-110-10=0

We add all the numbers together, and all the variables

x-120=0

We move all terms containing x to the left, all other terms to the right

x=120

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