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(3x-10)=(25)+(x+15)
We move all terms to the left:
(3x-10)-((25)+(x+15))=0
We get rid of parentheses
3x-(25+(x+15))-10=0
We calculate terms in parentheses: -(25+(x+15)), so:We get rid of parentheses
25+(x+15)
determiningTheFunctionDomain (x+15)+25
We get rid of parentheses
x+15+25
We add all the numbers together, and all the variables
x+40
Back to the equation:
-(x+40)
3x-x-40-10=0
We add all the numbers together, and all the variables
2x-50=0
We move all terms containing x to the left, all other terms to the right
2x=50
x=50/2
x=25
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