(3x-10)+50+(x+20)=180

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Solution for (3x-10)+50+(x+20)=180 equation: 



(3x-10)+50+(x+20)=180

We move all terms to the left:

(3x-10)+50+(x+20)-(180)=0

We add all the numbers together, and all the variables

(3x-10)+(x+20)-130=0

We get rid of parentheses

3x+x-10+20-130=0

We add all the numbers together, and all the variables

4x-120=0

We move all terms containing x to the left, all other terms to the right

4x=120

x=120/4

x=30

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