(3x-10)+(4x-100)+(2x)+(x)=360

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Solution for (3x-10)+(4x-100)+(2x)+(x)=360 equation: 



(3x-10)+(4x-100)+(2x)+(x)=360

We move all terms to the left:

(3x-10)+(4x-100)+(2x)+(x)-(360)=0

We add all the numbers together, and all the variables

3x+(3x-10)+(4x-100)-360=0

We get rid of parentheses

3x+3x+4x-10-100-360=0

We add all the numbers together, and all the variables

10x-470=0

We move all terms containing x to the left, all other terms to the right

10x=470

x=470/10

x=47

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