(3x-10)+(2x)=50

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Solution for (3x-10)+(2x)=50 equation: 



(3x-10)+(2x)=50

We move all terms to the left:

(3x-10)+(2x)-(50)=0

We add all the numbers together, and all the variables

2x+(3x-10)-50=0

We get rid of parentheses

2x+3x-10-50=0

We add all the numbers together, and all the variables

5x-60=0

We move all terms containing x to the left, all other terms to the right

5x=60

x=60/5

x=12

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