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(3x-10)(x+15)+25=180
We move all terms to the left:
(3x-10)(x+15)+25-(180)=0
We add all the numbers together, and all the variables
(3x-10)(x+15)-155=0
We multiply parentheses ..
(+3x^2+45x-10x-150)-155=0
We get rid of parentheses
3x^2+45x-10x-150-155=0
We add all the numbers together, and all the variables
3x^2+35x-305=0
a = 3; b = 35; c = -305;
Δ = b2-4ac
Δ = 352-4·3·(-305)
Δ = 4885
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-\sqrt{4885}}{2*3}=\frac{-35-\sqrt{4885}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+\sqrt{4885}}{2*3}=\frac{-35+\sqrt{4885}}{6} $
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