(3x-1)2-(2x+3)2=5(X-2)+(x-1)+(5x+2)

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Solution for (3x-1)2-(2x+3)2=5(X-2)+(x-1)+(5x+2) equation: 



(3x-1)2-(2x+3)2=5(x-2)+(x-1)+(5x+2)

We move all terms to the left:

(3x-1)2-(2x+3)2-(5(x-2)+(x-1)+(5x+2))=0

We multiply parentheses

6x-4x-(5(x-2)+(x-1)+(5x+2))-2-6=0



We calculate terms in parentheses: -(5(x-2)+(x-1)+(5x+2)), so:

5(x-2)+(x-1)+(5x+2)

We multiply parentheses

5x+(x-1)+(5x+2)-10

We get rid of parentheses

5x+x+5x-1+2-10

We add all the numbers together, and all the variables

11x-9

Back to the equation:

-(11x-9)



We add all the numbers together, and all the variables

2x-(11x-9)-8=0

We get rid of parentheses

2x-11x+9-8=0

We add all the numbers together, and all the variables

-9x+1=0

We move all terms containing x to the left, all other terms to the right

-9x=-1

x=-1/-9

x=1/9

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