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(3x-1)/5=(x-1)/3
We move all terms to the left:
(3x-1)/5-((x-1)/3)=0
We calculate fractions
3x/()+(-((x-1)*5)/()=0
We calculate terms in parentheses: +(-((x-1)*5)/(), so:We get rid of parentheses
-((x-1)*5)/(
We multiply all the terms by the denominator
-((x-1)*5)
We calculate terms in parentheses: -((x-1)*5), so:We get rid of parentheses
(x-1)*5
We multiply parentheses
5x-5
Back to the equation:
-(5x-5)
-5x+5
Back to the equation:
+(-5x+5)
3x/()-5x+5=0
We multiply all the terms by the denominator
3x-5x*()+5*()=0
We add all the numbers together, and all the variables
3x-5x*()=0
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