(3x-1)/5=(x+1)/3

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Solution for (3x-1)/5=(x+1)/3 equation: 



(3x-1)/5=(x+1)/3

We move all terms to the left:

(3x-1)/5-((x+1)/3)=0

We calculate fractions


3x/()+(-((x+1)*5)/()=0



We calculate terms in parentheses: +(-((x+1)*5)/(), so:

-((x+1)*5)/(

We multiply all the terms by the denominator


-((x+1)*5)



We calculate terms in parentheses: -((x+1)*5), so:

(x+1)*5

We multiply parentheses

5x+5

Back to the equation:

-(5x+5)



We get rid of parentheses

-5x-5

Back to the equation:

+(-5x-5)



We get rid of parentheses

3x/()-5x-5=0

We multiply all the terms by the denominator


3x-5x*()-5*()=0

We add all the numbers together, and all the variables

3x-5x*()=0

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