(3x-1)-4(2x+1)=4(4x-3)

Solution for (3x-1)-4(2x+1)=4(4x-3) equation:

(3x-1)-4(2x+1)=4(4x-3)

We move all terms to the left:

(3x-1)-4(2x+1)-(4(4x-3))=0

We multiply parentheses

(3x-1)-8x-(4(4x-3))-4=0

We get rid of parentheses

3x-8x-(4(4x-3))-1-4=0


We calculate terms in parentheses: -(4(4x-3)), so:

4(4x-3)

We multiply parentheses

16x-12

Back to the equation:

-(16x-12)


We add all the numbers together, and all the variables

-5x-(16x-12)-5=0

We get rid of parentheses

-5x-16x+12-5=0

We add all the numbers together, and all the variables

-21x+7=0

We move all terms containing x to the left, all other terms to the right

-21x=-7

x=-7/-21

x=1/3