(3x-1)-((2x-6)+(2x-5))=2

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Solution for (3x-1)-((2x-6)+(2x-5))=2 equation: 



(3x-1)-((2x-6)+(2x-5))=2

We move all terms to the left:

(3x-1)-((2x-6)+(2x-5))-(2)=0

We get rid of parentheses

3x-((2x-6)+(2x-5))-1-2=0



We calculate terms in parentheses: -((2x-6)+(2x-5)), so:

(2x-6)+(2x-5)

We get rid of parentheses

2x+2x-6-5

We add all the numbers together, and all the variables

4x-11

Back to the equation:

-(4x-11)



We add all the numbers together, and all the variables

3x-(4x-11)-3=0

We get rid of parentheses

3x-4x+11-3=0

We add all the numbers together, and all the variables

-1x+8=0

We move all terms containing x to the left, all other terms to the right

-x=-8

x=-8/-1

x=+8

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