(3x-1)+(x+11)+(2x+2)=180

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Solution for (3x-1)+(x+11)+(2x+2)=180 equation:



(3x-1)+(x+11)+(2x+2)=180
We move all terms to the left:
(3x-1)+(x+11)+(2x+2)-(180)=0
We get rid of parentheses
3x+x+2x-1+11+2-180=0
We add all the numbers together, and all the variables
6x-168=0
We move all terms containing x to the left, all other terms to the right
6x=168
x=168/6
x=28

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