(3x-1)+(3x+2)+(3x+6)+(2x+4)=36

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Solution for (3x-1)+(3x+2)+(3x+6)+(2x+4)=36 equation: 



(3x-1)+(3x+2)+(3x+6)+(2x+4)=36

We move all terms to the left:

(3x-1)+(3x+2)+(3x+6)+(2x+4)-(36)=0

We get rid of parentheses

3x+3x+3x+2x-1+2+6+4-36=0

We add all the numbers together, and all the variables

11x-25=0

We move all terms containing x to the left, all other terms to the right

11x=25

x=25/11

x=2+3/11

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