(3x-1)(x+2)+5x=(2x+1)(x-3)+x2

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Solution for (3x-1)(x+2)+5x=(2x+1)(x-3)+x2 equation: 



(3x-1)(x+2)+5x=(2x+1)(x-3)+x2

We move all terms to the left:

(3x-1)(x+2)+5x-((2x+1)(x-3)+x2)=0

We add all the numbers together, and all the variables

5x+(3x-1)(x+2)-((2x+1)(x-3)+x2)=0

We multiply parentheses ..

(+3x^2+6x-1x-2)+5x-((2x+1)(x-3)+x2)=0



We calculate terms in parentheses: -((2x+1)(x-3)+x2), so:

(2x+1)(x-3)+x2

We add all the numbers together, and all the variables

x^2+(2x+1)(x-3)

We multiply parentheses ..

x^2+(+2x^2-6x+x-3)

We get rid of parentheses

x^2+2x^2-6x+x-3

We add all the numbers together, and all the variables

3x^2-5x-3

Back to the equation:

-(3x^2-5x-3)



We get rid of parentheses

3x^2-3x^2+6x-1x+5x+5x-2+3=0

We add all the numbers together, and all the variables

15x+1=0

We move all terms containing x to the left, all other terms to the right

15x=-1

x=-1/15

x=-1/15

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