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(3x-1)(6-2x)=0
We add all the numbers together, and all the variables
(3x-1)(-2x+6)=0
We multiply parentheses ..
(-6x^2+18x+2x-6)=0
We get rid of parentheses
-6x^2+18x+2x-6=0
We add all the numbers together, and all the variables
-6x^2+20x-6=0
a = -6; b = 20; c = -6;
Δ = b2-4ac
Δ = 202-4·(-6)·(-6)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-16}{2*-6}=\frac{-36}{-12} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+16}{2*-6}=\frac{-4}{-12} =1/3 $
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