(3x-1)(3x+1)=2

Solution for (3x-1)(3x+1)=2 equation:

Simplifying
(3x + -1)(3x + 1) = 2

Reorder the terms:
(-1 + 3x)(3x + 1) = 2

Reorder the terms:
(-1 + 3x)(1 + 3x) = 2

Multiply (-1 + 3x) * (1 + 3x)
(-1(1 + 3x) + 3x * (1 + 3x)) = 2
((1 * -1 + 3x * -1) + 3x * (1 + 3x)) = 2
((-1 + -3x) + 3x * (1 + 3x)) = 2
(-1 + -3x + (1 * 3x + 3x * 3x)) = 2
(-1 + -3x + (3x + 9x2)) = 2

Combine like terms: -3x + 3x = 0
(-1 + 0 + 9x2) = 2
(-1 + 9x2) = 2

Solving
-1 + 9x2 = 2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 9x2 = 2 + 1

Combine like terms: -1 + 1 = 0
0 + 9x2 = 2 + 1
9x2 = 2 + 1

Combine like terms: 2 + 1 = 3
9x2 = 3

Divide each side by '9'.
x2 = 0.3333333333

Simplifying
x2 = 0.3333333333

Take the square root of each side:
x = {-0.577350269, 0.577350269}