(3x-0.5)+(5x-2)=2(2x+3)+10x-5

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Solution for (3x-0.5)+(5x-2)=2(2x+3)+10x-5 equation: 



(3x-0.5)+(5x-2)=2(2x+3)+10x-5

We move all terms to the left:

(3x-0.5)+(5x-2)-(2(2x+3)+10x-5)=0

We get rid of parentheses

3x+5x-(2(2x+3)+10x-5)-0.5-2=0



We calculate terms in parentheses: -(2(2x+3)+10x-5), so:

2(2x+3)+10x-5

We add all the numbers together, and all the variables

10x+2(2x+3)-5

We multiply parentheses

10x+4x+6-5

We add all the numbers together, and all the variables

14x+1

Back to the equation:

-(14x+1)



We add all the numbers together, and all the variables

8x-(14x+1)-2.5=0

We get rid of parentheses

8x-14x-1-2.5=0

We add all the numbers together, and all the variables

-6x-3.5=0

We move all terms containing x to the left, all other terms to the right

-6x=3.5

x=3.5/-6

x=-1/1.71428571429

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