(3x-(2x-7)-23)+(x-6)=90

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Solution for (3x-(2x-7)-23)+(x-6)=90 equation: 



(3x-(2x-7)-23)+(x-6)=90

We move all terms to the left:

(3x-(2x-7)-23)+(x-6)-(90)=0

We get rid of parentheses

(3x-(2x-7)-23)+x-6-90=0



We calculate terms in parentheses: +(3x-(2x-7)-23), so:

3x-(2x-7)-23

We get rid of parentheses

3x-2x+7-23

We add all the numbers together, and all the variables

x-16

Back to the equation:

+(x-16)



We add all the numbers together, and all the variables

x+(x-16)-96=0

We get rid of parentheses

x+x-16-96=0

We add all the numbers together, and all the variables

2x-112=0

We move all terms containing x to the left, all other terms to the right

2x=112

x=112/2

x=56

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